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anairene554
@anairene554
October 2020
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A soma de cinco números inteiros consecutivos é 110. Determine-os.
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GeysB
X+(X+1)+(X+2)+(X+3)+(X+4)=110
5x=110-10
X=100/5
X=20
Consequentemente os números são 20,21,22,23,24
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anairene554
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5x=110-10
X=100/5
X=20
Consequentemente os números são 20,21,22,23,24