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Afyonlu03
@Afyonlu03
April 2019
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A=(2y+1) (y-3)-(2y+1)²
Bonsoir, veuillez:
dévlopper et réduire A.
factoriser A.
Avec la forme qui semble la plus appropriée, résoudre A=0
Calculer A lorsque y= -2 puis y= 0
Merci
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winner123
Verified answer
Bonsoir
a = 2 y² - 6 y - ( 4 y² + 4 y + 1)
a = 2 y² - 6 y - 4 y² - 4 y - 1
a = - 2 y² - 10 y - 1
a = ( ( 2 y + 1) ( y - 3 - 2 y - 1)
a = ( 2 y - 1) ( - y - 4)
a = 0
soit 2 y - 1 = 0
2 y = 1 et y = 1/2
soit - y - 4 = 0
- y = 4
y = - 4
pour y = - 2
a = ( - 4 - 1) ( + 4 -4) = - 5 x 0 = 0
pour y = 0 a = - 1 x - 4 = 4
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Verified answer
Bonsoira = 2 y² - 6 y - ( 4 y² + 4 y + 1)
a = 2 y² - 6 y - 4 y² - 4 y - 1
a = - 2 y² - 10 y - 1
a = ( ( 2 y + 1) ( y - 3 - 2 y - 1)
a = ( 2 y - 1) ( - y - 4)
a = 0
soit 2 y - 1 = 0
2 y = 1 et y = 1/2
soit - y - 4 = 0
- y = 4
y = - 4
pour y = - 2
a = ( - 4 - 1) ( + 4 -4) = - 5 x 0 = 0
pour y = 0 a = - 1 x - 4 = 4