Articles
Register
Sign In
Search
Afyonlu03
@Afyonlu03
April 2019
1
34
Report
A=(2y+1) (y-3)-(2y+1)²
Bonsoir, veuillez:
dévlopper et réduire A.
factoriser A.
Avec la forme qui semble la plus appropriée, résoudre A=0
Calculer A lorsque y= -2 puis y= 0
Merci
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
winner123
Verified answer
Bonsoir
a = 2 y² - 6 y - ( 4 y² + 4 y + 1)
a = 2 y² - 6 y - 4 y² - 4 y - 1
a = - 2 y² - 10 y - 1
a = ( ( 2 y + 1) ( y - 3 - 2 y - 1)
a = ( 2 y - 1) ( - y - 4)
a = 0
soit 2 y - 1 = 0
2 y = 1 et y = 1/2
soit - y - 4 = 0
- y = 4
y = - 4
pour y = - 2
a = ( - 4 - 1) ( + 4 -4) = - 5 x 0 = 0
pour y = 0 a = - 1 x - 4 = 4
1 votes
Thanks 1
More Questions From This User
See All
Afyonlu03
June 2021 | 0 Respostas
thannnnnks!!!!!!!!!!!!!!!!!!!
Responda
Afyonlu03
June 2021 | 0 Respostas
merci bien de repondre
Responda
Afyonlu03
June 2021 | 0 Respostas
merci bien de m'aider
Responda
Afyonlu03
June 2021 | 0 Respostas
Responda
Afyonlu03
June 2021 | 0 Respostas
Faites moi l'exercice 5 merci les gens
Responda
Afyonlu03
June 2021 | 0 Respostas
Faites l'ex 23, que le a et b merci :))
Responda
Afyonlu03
June 2021 | 0 Respostas
Responda
Afyonlu03
June 2021 | 0 Respostas
Responda
Afyonlu03
June 2021 | 0 Respostas
Responda
Afyonlu03
June 2021 | 0 Respostas
Responda
×
Report "A=(2y+1) (y-3)-(2y+1)² Bonsoir, veuillez: dévlopper et réduire A. factoriser A. Avec la forme qui se.... Pergunta de ideia de Afyonlu03"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonsoira = 2 y² - 6 y - ( 4 y² + 4 y + 1)
a = 2 y² - 6 y - 4 y² - 4 y - 1
a = - 2 y² - 10 y - 1
a = ( ( 2 y + 1) ( y - 3 - 2 y - 1)
a = ( 2 y - 1) ( - y - 4)
a = 0
soit 2 y - 1 = 0
2 y = 1 et y = 1/2
soit - y - 4 = 0
- y = 4
y = - 4
pour y = - 2
a = ( - 4 - 1) ( + 4 -4) = - 5 x 0 = 0
pour y = 0 a = - 1 x - 4 = 4