Articles
Register
Sign In
Search
Salimabdallah2
@Salimabdallah2
April 2019
1
115
Report
Aider moi s'il vous plait
a) déterminé la forme canonique de f(x)=4X²-4X+4
b) déterminé la forme factoriser de f(x)=4(X-2)²-16
c) determiné la forme canonique de f(x)= 2(3-2X) (X+2)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
anno32
Bonjour
a) déterminé la forme canonique de f(x)=4X²-4X+4
d'abord simplifions 4x²-4x+4 = x²-x+1
calculons Δ
Δ = (-1)² - 4(1)(1) = 1 - 4 = -3
forme canonique
(x-1/2)² + 3/4
b) déterminé la forme factoriser de f(x)=4(X-2)²-16
f(x) = 4(X-2)²-16
= [2(x-2)+4][2(x-2)-4]
= (2x-4+4)(2x-4-4)
= (2x)(2x-8)
c) determiné la forme canonique de f(x)= 2(3-2X) (X+2)
f(x)= 2(3-2X) (X+2)
développons f(x)
f(x)= 2(3-2X) (X+2) = 2(3x+6-2x²-4x) = 6x+12-4x²-8x
f(x) = -4x² - 2x + 12
simplifions f(x) =-2x² - x + 6
calculons Δ
Δ = (-1)² - 4(-2)(6) = 1 + 48 = 49
Δ = 49
Forme canonique
-2(x+1/4)² - 49/16
la forme canonique c'est
a[(x+b/2a)² - Δ/4a²]
1 votes
Thanks 0
anno32
merci
More Questions From This User
See All
salimabdallah2
June 2021 | 0 Respostas
Responda
salimabdallah2
June 2021 | 0 Respostas
Responda
salimabdallah2
June 2021 | 0 Respostas
Responda
salimabdallah2
June 2021 | 0 Respostas
Responda
salimabdallah2
June 2021 | 0 Respostas
Responda
salimabdallah2
June 2021 | 0 Respostas
Responda
salimabdallah2
June 2021 | 0 Respostas
Responda
salimabdallah2
June 2021 | 0 Respostas
Responda
salimabdallah2
June 2021 | 0 Respostas
Responda
Salimabdallah2
April 2019 | 0 Respostas
Responda
×
Report "Aider moi s'il vous plait a) déterminé la forme canonique de f(x)=4X²-4X+4b) déterminé la forme fact.... Pergunta de ideia de Salimabdallah2"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
a) déterminé la forme canonique de f(x)=4X²-4X+4
d'abord simplifions 4x²-4x+4 = x²-x+1
calculons Δ
Δ = (-1)² - 4(1)(1) = 1 - 4 = -3
forme canonique
(x-1/2)² + 3/4
b) déterminé la forme factoriser de f(x)=4(X-2)²-16
f(x) = 4(X-2)²-16
= [2(x-2)+4][2(x-2)-4]
= (2x-4+4)(2x-4-4)
= (2x)(2x-8)
c) determiné la forme canonique de f(x)= 2(3-2X) (X+2)
f(x)= 2(3-2X) (X+2)
développons f(x)
f(x)= 2(3-2X) (X+2) = 2(3x+6-2x²-4x) = 6x+12-4x²-8x
f(x) = -4x² - 2x + 12
simplifions f(x) =-2x² - x + 6
calculons Δ
Δ = (-1)² - 4(-2)(6) = 1 + 48 = 49
Δ = 49
Forme canonique
-2(x+1/4)² - 49/16
la forme canonique c'est
a[(x+b/2a)² - Δ/4a²]