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Juju8787
@Juju8787
April 2019
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Aidez moi s'il vous plaît, c'es sur la factorisation !!
Consigne: Factoriser le premier membre de chaque équation, puis résoudre l'équation produit nul obtenue.
a. 5x²+3x=0
b.4(x+2)+(x-3)×(x+2)=0
c.(2x+3)×(5-2x)+(5-2x)×(9-x)=0
d.(x-7)²-(3-5x)×(x-7)=0
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manon60400
B. (x+2)(4+x-3)
a. x(5x+3)
c. (5-2x)(2x+3+9-x) ou (5-2x)(x+12)
d. (x-7)(x-7-3+5x) ou (x-7)(6x-10)
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a. x(5x+3)
c. (5-2x)(2x+3+9-x) ou (5-2x)(x+12)
d. (x-7)(x-7-3+5x) ou (x-7)(6x-10)