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Balsimoux
@Balsimoux
April 2019
2
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Aidez moi svp !
X = lettre ; * = multiplier par
F = x*x + 6x + 9
Vérifier que F = (x + 3) au carré
Or voilà ce que j'ai trouvé mais je ne trouve pas F = (x + 3) au carré
Merci de l'aide.
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telephone16
F = x X x + 6x + 9
x² + 6x +9
(x +3)² = x² +6x +9
F est bien = (x+3)²
0 votes
Thanks 1
Commentaires
F= x*x + 6x + 9
F = x² + 6x + 9
Pour trouver (x + 3)², il faut se servir de l'identité remarquable suivante :
(a + b)² = a² + 2ab + b²
Donc x² + 6x + 9
= x² + 2(x * 3) + 3²
= (x + 3)²
Vérifions :
(x + 3)²
= x² + 2*3x + 3²
= x² + 6x + 9
1 votes
Thanks 1
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Lista de comentários
x² + 6x +9
(x +3)² = x² +6x +9
F est bien = (x+3)²
F = x² + 6x + 9
Pour trouver (x + 3)², il faut se servir de l'identité remarquable suivante :
(a + b)² = a² + 2ab + b²
Donc x² + 6x + 9
= x² + 2(x * 3) + 3²
= (x + 3)²
Vérifions :
(x + 3)²
= x² + 2*3x + 3²
= x² + 6x + 9