AJUDA, POR FAVOR: Calcule a área dos trapézios, em metro.... Pergunta de ideia deEduardoRSilva

March 2022 1 46 Report

AJUDA, POR FAVOR: Calcule a área dos trapézios, em metro

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$S=\dfrac{(B+b)h}{2}$

d)

$h^2+9^2=15^2$

$h^2+81=225$

$h^2=144$

$h=12$

$b=20$

$B=20+9+9=39$

$S=\dfrac{(39+20)12}{2}=59\cdot6=354~\text{m}^2$ .

b) $h^2+2^2=(2\sqrt{10})^2$

$h^2+4=40$

$h^2=36$

$h=6$

$B=2+6+x$

$x^2+6^2=(6\sqrt{2})^2$

$x^2+36=72$

$x^2=36$

$x=6$

$B=2+6+6=14$

$S=\dfrac{(6+14)6}{2}=20\cdot3=60~\text{m}^2$ .

f) $\text{sen}~60^{\circ}=\dfrac{h}{4\sqrt{3}}$

$\dfrac{\sqrt{3}}{2}=\dfrac{h}{4\sqrt{3}}$

$2h=12$

$h=6$

$B=6+6+x=12+x$

$\text{cos}~60^{\circ}=\dfrac{x}{4\sqrt{3}}$

$\dfrac{1}{2}=\dfrac{x}{4\sqrt{3}}$

$x=2\sqrt{3}$

$B=12+2\sqrt{3}$

$S=\dfrac{(6+12+2\sqrt{3})4}{2}=(18+2\sqrt{2})2=36+4\sqrt{2}~\text{m}^2$

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