a) x²-7 = x+5
x²-x-7-5 = 0
x²-x-12 = 0
b) x²+11x = 16x-6
x²+11x-16x+6 = 0
x²-5x+6 = 0
c) x(x-6)+x² = (x-5)(x+2)
x²-6x+x² = x²+2x-5x-10
x²+x²-x²-6x+5x+10 = 0
x²-x+10 = 0
d) 2x²-7x+4 = 1-x²
2x²+x²-7x+4-1 = 0
3x²-7x+3 = 0
28/09/22
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a) x²-7 = x+5
x²-x-7-5 = 0
x²-x-12 = 0
b) x²+11x = 16x-6
x²+11x-16x+6 = 0
x²-5x+6 = 0
c) x(x-6)+x² = (x-5)(x+2)
x²-6x+x² = x²+2x-5x-10
x²+x²-x²-6x+5x+10 = 0
x²-x+10 = 0
d) 2x²-7x+4 = 1-x²
2x²+x²-7x+4-1 = 0
3x²-7x+3 = 0
❤️❤️ Prontinho ❤️❤️
28/09/22