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paulovitor2000
@paulovitor2000
October 2020
2
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aplicando a propriedade distributiva:
a 4√5 (√5+3)
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Henriqz
4√5 (√5+3)
4√25 + 12√5
4.5 + 12√5
20 + 12√5
2 votes
Thanks 3
paulovitor2000
brg
3478elc
Verified answer
Vai ficar: 4. V25 + 12 V5
4.5 + 12V5
20 + 12 V5.
Pronto.
0 votes
Thanks 1
paulovitor2000
obg
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Lista de comentários
4√5 (√5+3)
4√25 + 12√5
4.5 + 12√5
20 + 12√5
Verified answer
Vai ficar: 4. V25 + 12 V54.5 + 12V5
20 + 12 V5.
Pronto.