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Jeremy26i
@Jeremy26i
April 2019
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Bonjour, 1èreS, trigonométrie :
Exprimer les réels donnés en fonction de cos x ou de sin x.
Merci d'avance pour votre aide.
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MichaelS
Verified answer
Utilise les formules de d'additions :
cos(a+b) = cos(a)cos(b) - sin(a)sin(b)
cos(a-b) = cos(a)cos(b) + sin(a)sin(b)
sin(a+b) = sin(a)cos(b) + cos(a)sin(b)
sin(a-b) = sin(a)cos(b) - cos(a)sin(b)
exemple pour le A
A = cos(x - pi/2)
A = cos(x)cos(pi/2) + sin(x)sin(pi/2)
A = sin(x)
3 votes
Thanks 5
Jeremy26i
Ok! Merci bcp de tes explications !! :D
MichaelS
De rien :) si tu as besoin d'aide pour les autres, n'hésite pas ;)
Jeremy26i
Rebonsoir, j'ai fini l'exercice peux-tu me corriger? Merci (:
Jeremy26i
C= cos(7pi/2-x) = cos(-pi/2-x) = cos(pi/2+x) = - sin x
Jeremy26i
D= sin(x-pi/2)= - sin(pi/2-x) = - cos x
Jeremy26i
E = sin (x-3pi/2) = sin (x-(-pi/2)) = sin (pi/2) = cos x
Jeremy26i
F = sin (7pi/2-x) = sin(-pi/2 - x) = - sin (pi/2-x) = - cos x
MichaelS
oui c'est bon :)
Jeremy26i
Grâce à toi, merci encore ^^
MichaelS
de rien :)
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Verified answer
Utilise les formules de d'additions :cos(a+b) = cos(a)cos(b) - sin(a)sin(b)
cos(a-b) = cos(a)cos(b) + sin(a)sin(b)
sin(a+b) = sin(a)cos(b) + cos(a)sin(b)
sin(a-b) = sin(a)cos(b) - cos(a)sin(b)
exemple pour le A
A = cos(x - pi/2)
A = cos(x)cos(pi/2) + sin(x)sin(pi/2)
A = sin(x)