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1D2010
@1D2010
May 2019
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Bonjour à tous svp aider moi à résoudre cet exercice. merci d'avance
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scoladan
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Bonjour,
(toujours aussi flou)
1) Toutes les lampes sont identiques donc elles ont la même résistance.
I₁ = I₂ + I₃ = I₅ + I₆
I₄ = I₂ - I₅ = I₃ - I₆ = 0
Donc I₂ = I₃ = I₅ = I₆ = I₁/2 = 100 mA
2) I₁ = 300 mA I₂ = 100 mA I₄ = 50 mA
I₃ = I₁ - I₂ = 300 - 100 = 200 mA
I₅ = I₂ - I₄ = 100 - 50 = 50 mA
I₆ = I₃ + I₄ = 200 + 50 = 250 mA
3) I = I₅ + I₆ = 50 + 250 = 300 mA (= I₁ évidemment)
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Verified answer
Bonjour,(toujours aussi flou)
1) Toutes les lampes sont identiques donc elles ont la même résistance.
I₁ = I₂ + I₃ = I₅ + I₆
I₄ = I₂ - I₅ = I₃ - I₆ = 0
Donc I₂ = I₃ = I₅ = I₆ = I₁/2 = 100 mA
2) I₁ = 300 mA I₂ = 100 mA I₄ = 50 mA
I₃ = I₁ - I₂ = 300 - 100 = 200 mA
I₅ = I₂ - I₄ = 100 - 50 = 50 mA
I₆ = I₃ + I₄ = 200 + 50 = 250 mA
3) I = I₅ + I₆ = 50 + 250 = 300 mA (= I₁ évidemment)