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Orton
@Orton
April 2019
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Bonjour, aidé moi c'est urgent !
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Commentaires (2)
1) on peut faire 2 manieres,
soit tu sais que la diago d'un carré = cV2 ; AC = 4V2
comme AO es t a demi-diago = (4V2)/2 = 2V2
ou avec pyth :
AC² = AB²+BC²
= 4²+4²
= 32
AC = V32 =4V2
AO =AC/2 = 4V2/2 = 2V2
2) SO² = SA²-AO²
= 4²-(2V2)²
= 16-8
= 8
SO =V8 =2V2
3) V SABCD =1/3(4²*2V2)
= 1/3(32V2)
= (32V2)/3
2 votes
Thanks 2
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Lista de comentários
soit tu sais que la diago d'un carré = cV2 ; AC = 4V2
comme AO es t a demi-diago = (4V2)/2 = 2V2
ou avec pyth :
AC² = AB²+BC²
= 4²+4²
= 32
AC = V32 =4V2
AO =AC/2 = 4V2/2 = 2V2
2) SO² = SA²-AO²
= 4²-(2V2)²
= 16-8
= 8
SO =V8 =2V2
3) V SABCD =1/3(4²*2V2)
= 1/3(32V2)
= (32V2)/3