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DeryaDobrev
@DeryaDobrev
April 2019
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Bonjour comment pourrais-je calculer
[10-(1-3x)+x(3x+x)]
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Cipou
10-1+3x+x*4x = 9+3x+4x²
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Cipou
pour que tu puisses enlever qqchose d'un côté il faut qu'il soit aussi de l'autre côté
Cipou
attends, laisse tomber ça mène à rien. Je cherche autre chose
Cipou
alors, si on reprend à (9+3x+3x²+x²)=0 tu vois où on est ?
Cipou
bon, tu continues avec (9+x(3+3x+x))=0
Cipou
ah d'accord ! derien, j'ai rien fait ;)
hayakadi
En premier tu developpes x dans x(3x+x):
[10-(1-3x)+(3
+
)]
[10-1-3x+3
+
]
et tu continues
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[10-(1-3x)+(3
[10-1-3x+3
et tu continues