Bonsoir,
2) (4x-5)(2x+1) + 12x-15 = (4x-5)(2x+1) + 3(4x-5) = (4x-5)(2x+1+3) = (4x-5)(2x+4)
3) (3x-2)(x+1)-(x+1)² = 3x²+3x-2x-2 - (x²+2x+1) = 3x²-x²+3x-2x-2x-2-1 = 2x²-x-3
4) [(5x-7)(2x+8)] / (3x+3) = 0 ⇒ (5x-7)(2x+8) = 0 ⇒ 5x-7=0 ou 2x+8=0 ⇒ 5x=7 ou 2x=-8 ⇒ x=7/5 ou x=-8/2=-4
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Bonsoir,
2) (4x-5)(2x+1) + 12x-15 = (4x-5)(2x+1) + 3(4x-5) = (4x-5)(2x+1+3) = (4x-5)(2x+4)
3) (3x-2)(x+1)-(x+1)² = 3x²+3x-2x-2 - (x²+2x+1) = 3x²-x²+3x-2x-2x-2-1 = 2x²-x-3
4) [(5x-7)(2x+8)] / (3x+3) = 0 ⇒ (5x-7)(2x+8) = 0 ⇒ 5x-7=0 ou 2x+8=0 ⇒ 5x=7 ou 2x=-8 ⇒ x=7/5 ou x=-8/2=-4