Articles
Register
Sign In
Search
Saleh2
@Saleh2
May 2019
1
47
Report
Bonjour, j’ai du mal à comprendre et j’ai besoin de votre aide svp aidez moi pour ces deux exercices svp
Merci d’avance
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
ProfdeMaths1
Verified answer
1) A milieu de [MB] ⇒ MA=AB
CABN parallélogramme ⇒ CN=AB
MA=AB ⇒ CN=MA ⇒ CMAN parallélogramme
ABCD parallélogramme ⇒ DC=AB ⇒ DC=CN ⇒ C milieu de [DN]
2) EF(6+5,-2-7)=(11;-9) , HG=(11-0;0-9)=(11;-9) ⇒ EF=HG
⇒ EFGH parallélogramme
EG(16;-7) et FK(-16;7) ⇒ EG=KF ⇒ EGKF n'est pas parallélogramme
0 votes
Thanks 3
More Questions From This User
See All
saleh2
January 2021 | 0 Respostas
Responda
saleh2
January 2021 | 0 Respostas
Responda
saleh2
January 2021 | 0 Respostas
Responda
Saleh2
May 2019 | 0 Respostas
Responda
Saleh2
May 2019 | 0 Respostas
Responda
Recomendar perguntas
mehdizone4
November 2022 | 0 Respostas
carla3096
November 2022 | 0 Respostas
lilastark77
October 2022 | 0 Respostas
louise5654
October 2022 | 0 Respostas
charliegumezy
October 2022 | 0 Respostas
maguyungudimayoyolod
October 2022 | 0 Respostas
nounou8448
October 2022 | 0 Respostas
kenan93
October 2022 | 0 Respostas
juju56789
October 2022 | 0 Respostas
nhvabesoindaidesvp
October 2022 | 0 Respostas
×
Report "Bonjour, j’ai du mal à comprendre et j’ai besoin de votre aide svp aidez moi pour ces deux exercices.... Pergunta de ideia de Saleh2"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
1) A milieu de [MB] ⇒ MA=ABCABN parallélogramme ⇒ CN=AB
MA=AB ⇒ CN=MA ⇒ CMAN parallélogramme
ABCD parallélogramme ⇒ DC=AB ⇒ DC=CN ⇒ C milieu de [DN]
2) EF(6+5,-2-7)=(11;-9) , HG=(11-0;0-9)=(11;-9) ⇒ EF=HG
⇒ EFGH parallélogramme
EG(16;-7) et FK(-16;7) ⇒ EG=KF ⇒ EGKF n'est pas parallélogramme