Articles
Register
Sign In
Search
Dewar
@Dewar
May 2019
1
68
Report
Bonjour ! J'ai un exercice à faire sur la loi exponentielle et je galère. Merci pour votre aide ! Le voici :
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
scoladan
Verified answer
Bonjour,
X loi exponentielle de paramètre 0,1
1) p(X≥15)
= 1 - p(X<15)
= 1 - e^(0,1x15)
= 1 - 0,7769
= 0,2231 à 10⁻⁴ près.
2) p(5<X<25)
= p(X<25) - p(X<5)
= 0,9179 - 0,3935
= 0,5244
3) p(X>30) sachant que X>15
= p(15>X>30)/p(X>15) (intersection/condition)
= (p(X≤30 - p(X≤15))/(1 - p(X≤15))
= 0,1733/0,7769
= 0,2230
2 votes
Thanks 1
Dewar
Merci beaucoup !
More Questions From This User
See All
Dewar
February 2021 | 0 Respostas
Responda
Dewar
January 2021 | 0 Respostas
Responda
Dewar
January 2021 | 0 Respostas
Responda
Dewar
January 2021 | 0 Respostas
Responda
Dewar
January 2021 | 0 Respostas
Responda
Dewar
January 2021 | 0 Respostas
Responda
Dewar
January 2021 | 0 Respostas
Responda
Dewar
January 2021 | 0 Respostas
Responda
Dewar
January 2021 | 0 Respostas
Responda
Dewar
January 2021 | 0 Respostas
Responda
×
Report "Bonjour ! J'ai un exercice à faire sur la loi exponentielle et je galère. Merci pour votre aide ! Le.... Pergunta de ideia de Dewar"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjour,X loi exponentielle de paramètre 0,1
1) p(X≥15)
= 1 - p(X<15)
= 1 - e^(0,1x15)
= 1 - 0,7769
= 0,2231 à 10⁻⁴ près.
2) p(5<X<25)
= p(X<25) - p(X<5)
= 0,9179 - 0,3935
= 0,5244
3) p(X>30) sachant que X>15
= p(15>X>30)/p(X>15) (intersection/condition)
= (p(X≤30 - p(X≤15))/(1 - p(X≤15))
= 0,1733/0,7769
= 0,2230