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84560
@84560
May 2019
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Bonjour, j'ai un exercice de maths niveau 3ème mais je ne comprends pas, pouvais vous m'aidez s.v.p merci.
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calinizou
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Bonsoir bon je t'aide un peu
tu as 5 produits
(x-9)²
x(x-9)
(x-3)²
3(x-9(x+3)(x-3)
tu développes
(x-9)²=x²-18x+81 donc x²-2*x*9+9²
x(x-9)=x²-9x
(x-3)²=x²-6x+9
3(x-9)=3x-27 donc 3x-3*9
(x+3)(x-3)=x²-3x+3x-9=x²-9
*veut dire multiplier
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Thanks 1
84560
mzerci beaucoup j'ai compris .
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Verified answer
Bonsoir bon je t'aide un peutu as 5 produits
(x-9)²
x(x-9)
(x-3)²
3(x-9(x+3)(x-3)
tu développes
(x-9)²=x²-18x+81 donc x²-2*x*9+9²
x(x-9)=x²-9x
(x-3)²=x²-6x+9
3(x-9)=3x-27 donc 3x-3*9
(x+3)(x-3)=x²-3x+3x-9=x²-9
*veut dire multiplier