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margaux9046
@margaux9046
May 2023
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bonjour, j’ai un exercice de physique chimie à faire pour DEMAIN !! pouvez vous m’aider svp
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Spleen97410
La masse du morceau de sucre =5,0g soit 5,0x10^-3kg
m.saccharose=5,70x10^-25kg
a. m.sucre / m.saccharose
5,0x10^-3 /5,70x10^-25 = 8,77x10^21
Il y a 8,77x10^21 molécules de saccharose dans le morceau de sucre.
b. n=m/M
M(saccharose)= 12xM(C)+22xM(H)+11xM(O) = 342g/mol
n= 5,70x10^-25x10^3/342 = 1,67x10^-24 mol
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m.saccharose=5,70x10^-25kg
a. m.sucre / m.saccharose
5,0x10^-3 /5,70x10^-25 = 8,77x10^21
Il y a 8,77x10^21 molécules de saccharose dans le morceau de sucre.
b. n=m/M
M(saccharose)= 12xM(C)+22xM(H)+11xM(O) = 342g/mol
n= 5,70x10^-25x10^3/342 = 1,67x10^-24 mol