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ZentoGaming
@ZentoGaming
May 2019
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Bonjour, j'ai un petit exo à faire en math mais j'ai aucune idée de comment faire et quoi utiliser !
ça serait avec plaisir que j'accepte votre aide !
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laurance
D'après la formule des resistances ici
1/x = 1/2 + 1/(x+3) et 1/x - 1/(x+3)= 1/2 puis
((x+3) - x )2 = 1x(x+3) donne 6 = x² + 3x
6= (x +1,5)² - 1,5² (x + 1,5)² = 6 +1,5² = 8,25
x + 1,5 = rac(8,25)
x = rac( 8,25) - 1,5 = 1,37 environ
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1/x = 1/2 + 1/(x+3) et 1/x - 1/(x+3)= 1/2 puis
((x+3) - x )2 = 1x(x+3) donne 6 = x² + 3x
6= (x +1,5)² - 1,5² (x + 1,5)² = 6 +1,5² = 8,25
x + 1,5 = rac(8,25)
x = rac( 8,25) - 1,5 = 1,37 environ