bonjour,
f (0) = - 3 et f( 4) = 5
( 5 + 3 ) / ( 4 - 0) = 8/4 = 2
ax = 2
f (4) = 5
4*2 + b = 5 ⇔ b = 5 - 8 = - 3
f (x) = 2 x - 3 d'où f(0) = - 3
g ( 0 ) = 2 et g ( 1) = - 1
( - 1 - 2 ) / ( 1 - 0 ) = - 3
ax = - 3
g(0) = 2 donc b = 2
g(x) = - 3 x + 2 d'où g ( 1) = - 3 + 2 = - 1
le reste est de la lecture graphique
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bonjour,
f (0) = - 3 et f( 4) = 5
( 5 + 3 ) / ( 4 - 0) = 8/4 = 2
ax = 2
f (4) = 5
4*2 + b = 5 ⇔ b = 5 - 8 = - 3
f (x) = 2 x - 3 d'où f(0) = - 3
g ( 0 ) = 2 et g ( 1) = - 1
( - 1 - 2 ) / ( 1 - 0 ) = - 3
ax = - 3
g(0) = 2 donc b = 2
g(x) = - 3 x + 2 d'où g ( 1) = - 3 + 2 = - 1
le reste est de la lecture graphique