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DefiRobot
@DefiRobot
January 2021
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Bonjour, J'aurais besoin d'aide svp pour un exercice de math .
Factoriser au maximum les expression suivantes :
1. 2x² - 4x
2. 4(x+7)²- (x+7) (2x - 12 )
3. x² - 4x+x
4. (x-4)² - 25
Merci d'avance pour l'aide !
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PetiteKyojo
Bonjour,
1. 2x² - 4x = 2x(x-2)
2. 4(x+7)²- (x+7) (2x - 12 )=
(x+7)[4(x+7)-(2x-12)]=
(x+7)(4x+28-2x+12)=
(x+7)(2x+40)=
2(x+7)(x+20)
3. x² - 4x+x
x²-3x =
x(x-3)
4. (x-4)² - 25 = a²-b² = (a-b)(a+b)
(x-4-5)(x-4+5) =
(x-9)(x+1)
2 votes
Thanks 0
DefiRobot
Merci de ton aide
DefiRobot
mais comment j'peux etre
PetiteKyojo
De rien!
DefiRobot
sur que c'est la bonne reponce
PetiteKyojo
Lol , c'est factoriser comme tu l'as demander.
DefiRobot
MERCI
PetiteKyojo
De rien
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Lista de comentários
1. 2x² - 4x = 2x(x-2)
2. 4(x+7)²- (x+7) (2x - 12 )=
(x+7)[4(x+7)-(2x-12)]=
(x+7)(4x+28-2x+12)=
(x+7)(2x+40)=
2(x+7)(x+20)
3. x² - 4x+x
x²-3x =
x(x-3)
4. (x-4)² - 25 = a²-b² = (a-b)(a+b)
(x-4-5)(x-4+5) =
(x-9)(x+1)