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ALFAB
@ALFAB
January 2021
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Bonjour, je bloque pour résoudre cette équation de niveau 1ere.
Merci à ceux qui m'aideront !
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trudelmichel
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Bonjour,
(1/x²+x-2)-(2/-3x²-5x+2)=0
mettons au même dénominateur
((-3x²-5x+2)/(x²+x-2)(-3x²-5x+2))-(2(x²+x-2)/(-3x²-5x+2)(x²+x-2))=0
(-3x²-5x+2)-2(x²+x-2)=0
-3²-5x+2-2x²-2x+4=0
-5x²-7x+6=0
delta=b²-4ac
delta=7²-(-5)(6)
delta=49+120=169
racine delta=13
x=-b+racdelta/2a
x=(+7+13)10=20/10=2
x=-b-rac delta/2a=+7-13/10=-6/10=0.6
1 votes
Thanks 1
ALFAB
merci beaucoup !
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Verified answer
Bonjour,(1/x²+x-2)-(2/-3x²-5x+2)=0
mettons au même dénominateur
((-3x²-5x+2)/(x²+x-2)(-3x²-5x+2))-(2(x²+x-2)/(-3x²-5x+2)(x²+x-2))=0
(-3x²-5x+2)-2(x²+x-2)=0
-3²-5x+2-2x²-2x+4=0
-5x²-7x+6=0
delta=b²-4ac
delta=7²-(-5)(6)
delta=49+120=169
racine delta=13
x=-b+racdelta/2a
x=(+7+13)10=20/10=2
x=-b-rac delta/2a=+7-13/10=-6/10=0.6