bjr
aire BCEF = (2x-3)² - (2x-3) (x+1)
donc aire BCEF = (2x-3) (2x-3-x-1) = (2x-3) (x-4)
Q4
si x= 5
alors aire BCEF = (2*5 - 3) (5-4) = 7 * 1 = 7
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bjr
aire BCEF = (2x-3)² - (2x-3) (x+1)
donc aire BCEF = (2x-3) (2x-3-x-1) = (2x-3) (x-4)
Q4
si x= 5
alors aire BCEF = (2*5 - 3) (5-4) = 7 * 1 = 7