bonjour

1. MASSE MOLAIRE

M (Cu) = 63.5

M(S) = 32.1

M(O) = 16

Donc

M(CuSO4)= M(Cu)+M(S)+M(O)×4

= 63.5 + 32.1 + 16x4 = 159.6 g/mol

2. MASSE A PRELEVER

m = n x M

m = 0.137 x 159.6

m = 21.86 g

3. NOMBRE DE MOLECULE

n = m/M = 21.86 / 159.6 = 0.13 mol