Réponse :
1) Let f(m) = -4m² + 8m + 12
=> f'(m) = -8m+8
At turning point, m=1
f(m) is increasing in the interval ]-∞, -1[ U ]3, ∞[
f(m) is decreasing in the interval ]-1, 3[
2) For P(x) to have double roots, ∆=b²-4ac=0
=> (2m+2)²-4(2)(m²-1)=0
=> 4m²+8m+4-8m²+8=0
=> -4m²+8m+12=0
=> m= -1 or m=3
For m= -1, => 2x² = 0
=> x = 0
For m= 3, => 2x²+8x+8 = 0
=> x = 2
3) For P(x) to have distinct roots, ∆=b²-4ac>0
=> 2m+2)²-4(2)(m²-1)>0
=> 4m²+8m+4-8m²+8>0
=> -4m²+8m+12>0
=> -1 < m < 3
the possible values of m are { 0, 1, 2}
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Verified answer
Réponse :
1) Let f(m) = -4m² + 8m + 12
=> f'(m) = -8m+8
At turning point, m=1
f(m) is increasing in the interval ]-∞, -1[ U ]3, ∞[
f(m) is decreasing in the interval ]-1, 3[
2) For P(x) to have double roots, ∆=b²-4ac=0
=> (2m+2)²-4(2)(m²-1)=0
=> 4m²+8m+4-8m²+8=0
=> -4m²+8m+12=0
=> m= -1 or m=3
For m= -1, => 2x² = 0
=> x = 0
For m= 3, => 2x²+8x+8 = 0
=> x = 2
3) For P(x) to have distinct roots, ∆=b²-4ac>0
=> 2m+2)²-4(2)(m²-1)>0
=> 4m²+8m+4-8m²+8>0
=> -4m²+8m+12>0
=> -1 < m < 3
the possible values of m are { 0, 1, 2}