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Siazzle
@Siazzle
May 2019
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Bonjour! Pouvez m’aider à trouver la limite de f(x) = (1+lnx) au carré -2x lorsque x tend vers 0
Merci
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croisierfamily
Verified answer
Lim [ (1+Lnx)² - 2x ] pour x tendant vers zéro = lim (1+Lnx)² = lim [1+2Lnx + (Lnx)² ]
= 1 + lim [ Lnx ( 2 + Lnx ) ] = 1 + lim (Lnx)²
= lim (Lnx)²
= + infini
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Verified answer
Lim [ (1+Lnx)² - 2x ] pour x tendant vers zéro = lim (1+Lnx)² = lim [1+2Lnx + (Lnx)² ]= 1 + lim [ Lnx ( 2 + Lnx ) ] = 1 + lim (Lnx)²
= lim (Lnx)²
= + infini