Verified answer

bonsoir

Comme tu m'as  demandé , je te fais les 6 premières

A =  (-2x+3)(x+2)    on applique la distributivité

-2x(x+2)+3(x+2)

-2x²-4x+3x+6

A= -2x²-x+6

B= (-7x-5)(4-2x)

-7x(4-2x)-5(4-2x)

-28x +14x² +20 +10x

B=14x² -18x -20

C= (-5x+2)(x-3)

-5x(x-3)+2(x-3)

-5x² +15x +2x -6

C =-5x² +17x -6

D= -(3x+4)(x+2)

(-3x-4)(x-2)

-3x (x+2) -4(x+2)

-3x² -6x -4x -8

D = -3x² -10x -8

E= - (2x-1)(3x-5)

(-2x+1)+(3x-5)

-2x(3x-5)+1(3x-5)

- 6x² +10x +3x -5

E = -6x² +13x -5

F = - (2x+4)(x-1)

(-2x-4)(x-1)

-2x(x-1)-4(x-1)

-2x² +2x -4x +4

F =-2x² -2x +4