Bonjour,
1) (d+2)²+(d+2)(d-3)
2) (d+2)²+(d+2)(d-3) = (d+2)(d+2)+(d+2)(d-3)
= (d+2)[(d+2)+(d-3)]
= (d+2)(2d-1)
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Bonjour,
1) (d+2)²+(d+2)(d-3)
2) (d+2)²+(d+2)(d-3) = (d+2)(d+2)+(d+2)(d-3)
= (d+2)[(d+2)+(d-3)]
= (d+2)(2d-1)