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impinkdinosaur
@impinkdinosaur
January 2021
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Bonjour, pouvez vous m'aider pour le
B
de cet exercice svp
Merci d'avance
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scoladan
Verified answer
Bonjour,
a) n(éo) = C x V
avec C = 1,2.10⁻³ mol.L⁻¹ et V = 50 mL = 50.10⁻³ L
soit n(éo) = 1,2.10⁻³ x 50.10⁻³ = 6,0.10⁻⁵ mol
b) il faut n(éo) = C₁ x Vp
soit Vp = n(éo)/C₁ = 6,0.10⁻⁵/3.10⁻³ = 2.10⁻² L = 20 mL
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Lista de comentários
Verified answer
Bonjour,a) n(éo) = C x V
avec C = 1,2.10⁻³ mol.L⁻¹ et V = 50 mL = 50.10⁻³ L
soit n(éo) = 1,2.10⁻³ x 50.10⁻³ = 6,0.10⁻⁵ mol
b) il faut n(éo) = C₁ x Vp
soit Vp = n(éo)/C₁ = 6,0.10⁻⁵/3.10⁻³ = 2.10⁻² L = 20 mL