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MzelleCelia
@MzelleCelia
January 2021
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Bonjour, pouvez vous m'aider s'il vous plait ?
J'ai besoin que l'on me guide pour résoudre ce problème ci
Merci
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scoladan
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Bonjour,
Variations de (g-f) :
(g-f)'(x) = g'(x) - f'(x)
Or g'(x) ≥ f'(x) sur I
Donc g'(x) - f'(x) ≥ 0
⇒ (g - f) est croissante sur I
⇒ Pour tout x ∈ [0;1], g(x) - f(x) ≥ 0
⇔ f(x) ≤ g(x)
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Bonjour,Variations de (g-f) :
(g-f)'(x) = g'(x) - f'(x)
Or g'(x) ≥ f'(x) sur I
Donc g'(x) - f'(x) ≥ 0
⇒ (g - f) est croissante sur I
⇒ Pour tout x ∈ [0;1], g(x) - f(x) ≥ 0
⇔ f(x) ≤ g(x)