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flo7321
@flo7321
January 2021
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Bonjour pouvez vous m'aider s'il vous plaît pour le C et D. Merci d'avance
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Leopoldine1
Bonjour :
Factoriser :
C = 16x²-(2x-3)²
C = (4x)²-(2x-3)²
(4x)²-(2x-3)² il prend la forme de a²-b² = (a-b)(a+b)
Alors :
C = (4x-2x+3)(4x-2x-3)
C = (2x+3)(2x-3)
________________________
D = (3-x)²-(2x+7)²
(3-x)²-(2x+7)² il prend la forme de a²-b² = (a-b)(a+b)
Alors :
D = (3-x-2x-7)(3-x+2x+7)
D = (3-7-x-2x)(3+7-x+2x)
D = (5-3x)(10+x)
J’espère t'avoir t'aider
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Thanks 0
flo7321
Oui
Leopoldine1
C'est un dm de 3e?
flo7321
Oui
nini999
Verified answer
C'est les identités remarquables
0 votes
Thanks 1
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Lista de comentários
Factoriser :
C = 16x²-(2x-3)²
C = (4x)²-(2x-3)²
(4x)²-(2x-3)² il prend la forme de a²-b² = (a-b)(a+b)
Alors :
C = (4x-2x+3)(4x-2x-3)
C = (2x+3)(2x-3)
________________________
D = (3-x)²-(2x+7)²
(3-x)²-(2x+7)² il prend la forme de a²-b² = (a-b)(a+b)
Alors :
D = (3-x-2x-7)(3-x+2x+7)
D = (3-7-x-2x)(3+7-x+2x)
D = (5-3x)(10+x)
J’espère t'avoir t'aider
Verified answer
C'est les identités remarquables