Articles
Register
Sign In
Search
emezenoula
@emezenoula
January 2021
1
72
Report
Bonjour.j'aurai besoin d'aide sur cet exercice.merci d'avance
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
aymanemaysae
Bonjour ;
1)
2) Soit
donc
donc on a :
,
donc le noyau de f est : (0;0) .
3) f est bijective si M est inversible , c-à-d si det(M)≠ 0 .
f est bijective .
1 votes
Thanks 1
More Questions From This User
See All
emezenoula
January 2021 | 0 Respostas
Responda
emezenoula
January 2021 | 0 Respostas
Responda
emezenoula
January 2021 | 0 Respostas
Responda
emezenoula
January 2021 | 0 Respostas
Responda
emezenoula
January 2021 | 0 Respostas
Responda
emezenoula
January 2021 | 0 Respostas
Responda
emezenoula
January 2021 | 0 Respostas
Responda
emezenoula
January 2021 | 0 Respostas
bonsoir.besoin d'aide sur cet exercice ppur demain.merci d'avance
Responda
emezenoula
January 2021 | 0 Respostas
Responda
emezenoula
January 2021 | 0 Respostas
bonsoir quelqu'un peut m'aider sur cet exercice .
Responda
×
Report "Bonjour.j'aurai besoin d'aide sur cet exercice.merci d'avance.... Pergunta de ideia de emezenoula"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
1)
2) Soit
donc
donc on a : ,
donc le noyau de f est : (0;0) .
3) f est bijective si M est inversible , c-à-d si det(M)≠ 0 .
f est bijective .