bonsoir.besoin d'aide sur cet exercice ppur demain.merci d'avance.... Pergunta de ideia deemezenoula

emezenoula @emezenoula

January 2021 1 168 Report

bonsoir.besoin d'aide sur cet exercice ppur demain.merci d'avance

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ramzi13 a) x=2α+1/2
y=α-3

y=α-3 ⇔ -2y=-2(α-3) ⇔ -2y=-2α+6
alors : x+(-2y)=(2α+1/2)+(-2α+6)
x-2y=2α+1/2-2α+6
x-2y=1/2+6
x-2y=13/2
2y=x-13/2
y=(x-13/2)/2
y=1/2 x -13/4
.................................
b) x=α
y=-3α-1/4

x=α⇔ 3x=3α
alors: 3x+y=3α+(-3α-1/4)
3x+y=3α-3α-1/4
3x+y=-1/4
y=-3x-1/4
.................................
c) x=α
y=-α
donc : x+y=α+(-α)
x+y=0

1 votes Thanks 1

emezenoula merci beaucoup.

ramzi13 de rien ;

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bonsoir quelqu'un peut m'aider sur cet exercice .

emezenoula January 2021 | 0 Respostas

salut les amis.j'aurai besoin d'aide sur cet exercice .merci d'avance

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