Bonsoir à tous savoir aider moi à calculer ces deux limites.Merci d'avance !.... Pergunta de ideia de1D2010

May 2019 1 149 Report

Bonsoir à tous savoir aider moi à calculer ces deux limites.

Merci d'avance !

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caylus

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Bonjour,

$\lim_{x \to \frac{1}{2}} \dfrac{tan(\pi x)}{\sqrt{-8x^2+8x+2}-2}\\=\frac{\infty}{0}=\infty*\infty=\infty\\\\L=\lim_{x \to \frac{1}{4}}\dfrac{tan(\pi x)-1}{16x^2-1}=\dfrac{0}{0}\\\\\Longrightarrow\ L=\lim_{x \to \frac{1}{4}}\dfrac{\pi}{cos^2(\pi*x)}*\dfrac{1}{32x}=\dfrac{\pi}{4}$

En utilisant la règle de l'Hospital.

0 votes Thanks 1

1D2010 OK en tous cas merci bcp

1D2010 donc. ..

1D2010 je dois appliquer ces formules ?

1D2010 merci

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