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Elo15
@Elo15
May 2022
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Bonsoir pouvez vous m’aider à trouver la dérivée de cette fonction svp.
Merci
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Skabetix
Bonjour,formule du cours à connaître : (e^u)' = u'×(e^u)ainsi : g(x) = 4e^(5x² - x) g'(x) = 4 × (10x - 1) × e^(5x² - x) = (40x - 4)e^(5x² - x)
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Elo15
Merci beaucoup !
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