Bonjour,
On a ln(1) = 0 ; n ln(a) = ln(aⁿ) et ln(a) + ln(b) = ln(a.b)
Donc
C = 4 ln(3) + 2 ln(5) + 4 ln(1)
C = ln(3⁴) + ln(5²)
C = ln(81) + ln(25)
C = ln(81 × 25)
C = ln(2 025)
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Bonjour,
On a ln(1) = 0 ; n ln(a) = ln(aⁿ) et ln(a) + ln(b) = ln(a.b)
Donc
C = 4 ln(3) + 2 ln(5) + 4 ln(1)
C = ln(3⁴) + ln(5²)
C = ln(81) + ln(25)
C = ln(81 × 25)
C = ln(2 025)