bonsoir pouvez-vous m'aider pour la question 2a s'il vous plaît merci d'avance.... Pergunta de ideia detyssianaa

tyssianaa @tyssianaa

January 2021 1 76 Report

bonsoir pouvez-vous m'aider pour la question 2a s'il vous plaît merci d'avance

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Amateur Bonjour,
1) f(0)=3
f'(0)=4/1=4

2)
$f(x)= \dfrac{3x^2+ax+b}{x^2+1} \\\\

f'(x)= \dfrac{(6x+a)(x^2+1)-(3x^2+ax+b)*2*x}{(x^2+1)^2} \\\\
= \dfrac{-6x^3+ax^2+6x+a-6x^3-2ax^2-2bx}{(x^2+1)^2} \\\\
= \dfrac{-ax^2+(6-2b)x+a}{(x^2+1)^2} \\\\

$

1 votes Thanks 1

tyssianaa merci bcp❤

Amateur de rien

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