c) les triangles MDP et ABD sont -ils semblables
pour cela AB//MP
Donc on applique le théorème de THALES
DM/DA = DP/DB = MP/AB
sachant que AM = 3/7 AD
DM+AM = AD DM = AD - AM = AD - 3/7 AD = 4/7 AD
DM/DA = 4/7AD/AD = 4/7
DP/DB = MP/AB = 4/7 MP = 4/7 AB donc MP/AB = 4/7
Les 02 triangles sont semblables
d) BPN et BDC
PN//DC donc THEOREME DE THALES
BP/BD = BN/BC = PN/DC
BP = DB-DP
DB-DP/DB = 1 - DP/BD = 1-4/7 = 3/7
BP/BD = 3/7
PN/DC = 3/7 d'où PN = 3/7 x DC = 3/7 x 35 = 15 mm
BN/BC = PN/DC = 15/35 = 3/7
LES DEUX TRIANGLES SONT AUSSI SEMBLABLES
e) MP/AB = 4/7 MP = 4/7 x 28 = 16 mm
PN = 15 mm
MN = MP+PN = 15+16 = 31 mm
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c) les triangles MDP et ABD sont -ils semblables
pour cela AB//MP
Donc on applique le théorème de THALES
DM/DA = DP/DB = MP/AB
sachant que AM = 3/7 AD
DM+AM = AD DM = AD - AM = AD - 3/7 AD = 4/7 AD
DM/DA = 4/7AD/AD = 4/7
DP/DB = MP/AB = 4/7 MP = 4/7 AB donc MP/AB = 4/7
Les 02 triangles sont semblables
d) BPN et BDC
PN//DC donc THEOREME DE THALES
BP/BD = BN/BC = PN/DC
BP = DB-DP
DB-DP/DB = 1 - DP/BD = 1-4/7 = 3/7
BP/BD = 3/7
PN/DC = 3/7 d'où PN = 3/7 x DC = 3/7 x 35 = 15 mm
BN/BC = PN/DC = 15/35 = 3/7
LES DEUX TRIANGLES SONT AUSSI SEMBLABLES
e) MP/AB = 4/7 MP = 4/7 x 28 = 16 mm
PN = 15 mm
MN = MP+PN = 15+16 = 31 mm