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Safaeziyati
@Safaeziyati
May 2019
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Bonsoir. S'il vous plait pouvez-vous m'aider pour resoudrer cette equation: 2^x×3^y×7^z=7056
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loulakar
Verified answer
Bonsoir,
Il suffit juste de décomposer 7056 en nombre premier :
7056 = 2 x 2 x 2 x 2 x 7 x 7 x 3 x 3
Donc :
7056 = 2^x * 3^y * 7^z
x = 4
y = 2
z = 2
7056 = 2^4 * 3^2 * 7^2
3 votes
Thanks 1
loulakar
J'ai fait aucune technique jai juste cherché une décomposition du nombre en facteur premier
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Lista de comentários
Verified answer
Bonsoir,Il suffit juste de décomposer 7056 en nombre premier :
7056 = 2 x 2 x 2 x 2 x 7 x 7 x 3 x 3
Donc :
7056 = 2^x * 3^y * 7^z
x = 4
y = 2
z = 2
7056 = 2^4 * 3^2 * 7^2