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jiji5
@jiji5
January 2021
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BONSOIR svppp besoin d aide ! merci.
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laurance
1)delta=4-4(2m-1)=4(1-2m+1)= 8(1-m) il faut que
1-m>0 d'où m < 1
2)si m<1 alors x² -2x + 2m-1 =(x-alpha)(x-beta)=(x-a)(x-b)
x² -2x + 2m-1 = x² - (a+b)x + ab d'où a +b = 2 et ab = 2m-1
(a-1)(b-1)=ab - (a+b) +1 = 2m -1 - 2 + 1 = 2m-2
équation 2m-2= -10 2m= -8
m= -4 <1
a²b+ab² =ab(a+b)= 2(2m-1)
équation
2(2m-1)= -42
2m-1 = -21
2m= -20
m= -10 <1
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jiji5
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svpppo c est juste un ptit exercice plss help
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Je veux juste savoir est ce que c est juste ! c est sur la comparaison dans IR
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svpp si vous pouvez m aider :)
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svp c est un exercice sur la comparaison dans IR plzz
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svp j ai besoin d aide ( c est urgent ) :)
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jiji5
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plsss heeeelp svp aidez moi ! :(
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jiji5
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heelp :( ps : tt en bas le deniers nombre c est 29/4
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Lista de comentários
1-m>0 d'où m < 1
2)si m<1 alors x² -2x + 2m-1 =(x-alpha)(x-beta)=(x-a)(x-b)
x² -2x + 2m-1 = x² - (a+b)x + ab d'où a +b = 2 et ab = 2m-1
(a-1)(b-1)=ab - (a+b) +1 = 2m -1 - 2 + 1 = 2m-2
équation 2m-2= -10 2m= -8 m= -4 <1
a²b+ab² =ab(a+b)= 2(2m-1)
équation
2(2m-1)= -42
2m-1 = -21
2m= -20
m= -10 <1