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jiji5
@jiji5
January 2021
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plsss c est facile mais je n arrive pas à le faite " heelllppp :( "
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laurance
(a+b)² =a² + 2ab +b²
(a-b)²=a²-2ab +b²
4ab = (a+b)² -(a-b)² = 1 -(a-b)² ≤ 1 donc ab ≤ 1/4
2(a²+b²) = (a+b)² + (a-b)² = 1 +(a-b)² ≥1
a² +b² ≥1/2
(a+1/a) ²+(b+1/b)²=a² +b² + 4 + (1/a²+1/b²) ≥ 1/2 +4 + (a²+b)² * 1/(ab)²
1/ab ≥ 4 et 1/(ab)²≥ 16 d'où (a²+b)² * 1/(ab)²≥ 1/2 *16 = 8
(a+1/a) ²+(b+1/b)²≥1/2+4+8 = 12,5 = 25/2
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jiji5
January 2021 | 0 Respostas
svpppo c est juste un ptit exercice plss help
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jiji5
January 2021 | 0 Respostas
Je veux juste savoir est ce que c est juste ! c est sur la comparaison dans IR
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jiji5
January 2021 | 0 Respostas
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jiji5
January 2021 | 0 Respostas
svpp si vous pouvez m aider :)
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jiji5
January 2021 | 0 Respostas
svp c est un exercice sur la comparaison dans IR plzz
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jiji5
January 2021 | 0 Respostas
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jiji5
January 2021 | 0 Respostas
svp j ai besoin d aide ( c est urgent ) :)
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jiji5
January 2021 | 0 Respostas
plsss heeeelp svp aidez moi ! :(
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jiji5
January 2021 | 0 Respostas
heelp :( ps : tt en bas le deniers nombre c est 29/4
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jiji5
January 2021 | 0 Respostas
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(a-b)²=a²-2ab +b²
4ab = (a+b)² -(a-b)² = 1 -(a-b)² ≤ 1 donc ab ≤ 1/4
2(a²+b²) = (a+b)² + (a-b)² = 1 +(a-b)² ≥1
a² +b² ≥1/2
(a+1/a) ²+(b+1/b)²=a² +b² + 4 + (1/a²+1/b²) ≥ 1/2 +4 + (a²+b)² * 1/(ab)²
1/ab ≥ 4 et 1/(ab)²≥ 16 d'où (a²+b)² * 1/(ab)²≥ 1/2 *16 = 8
(a+1/a) ²+(b+1/b)²≥1/2+4+8 = 12,5 = 25/2