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Ayselceline
@Ayselceline
April 2019
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BONSOIR URGENT POUR DEMAIN
a) Factoriser 16-x²
b)Factoriser 16-x²-(4-x)(8-3x)
c) Résoudre l'inéquation: 16-x²-(4-x)(8-3x) ≥0
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Sadjo
A). 16-x^2=4^2-x^2=(4-x)(4+x). b). 16-x^2-(4-x)(8-3x)=(4-x)[4+x-8+3x]=4*(4-x)(x-1). c). 16-x^2-(4-x)(8-3x)<=0 équivaut: (4-x)(4+x)>=(4-x)(8-3x). donc: 4+x>=8-3x donc 1>=x d'où x appartient [1;+infini[.
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