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Resposta:

[tex]2A+A=\\ \\ \\ \left[\begin{array}{ccc}-6&2\\4&0\end{array}\right] +\left[\begin{array}{ccc}-3&1\\2&0\end{array}\right] =\\ \\ \\ \left[\begin{array}{ccc}-6-3&2+1\\4+2&0+0\end{array}\right] \\ \\ \\ 2A+A=\left[\begin{array}{ccc}-9&3\\6&0\end{array}\right][/tex]

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[tex]B-2A=\\ \\ \left[\begin{array}{ccc}5&-4\\3&5\end{array}\right] -\left[\begin{array}{ccc}-6&2\\4&0\end{array}\right] =\\ \\ \\ \left[\begin{array}{ccc}5-(-6)&-4-2\\3-4&5-0\end{array}\right] =\\ \\ \\ B-2A=\left[\begin{array}{ccc}11&-6\\-1&5\end{array}\right][/tex]