Explicação passo-a-passo:

A. (3-x)³

(3-x)³ = (3-x)(3-x)(3-x)

= (3-x)(9-6x+x²)

= 27 - 27x + 9x² - x³

Então (3-x)³ = -x³ + 9x² - 27x + 27

B. (2y-3)³

(2y-3)³ = (2y-3)(2y-3)(2y-3)

= (2y-3)(4y²-12y+9)

= 8y³ - 36y² + 54y - 27

Portanto, (2y-3)³ = 8y³ -36y² + 54y - 27

C. (x-5)³

(x-5)³ = (x-5)(x-5)(x-5)

= (x-5)(x²-10x+25)

= x³ - 15x² + 75x - 125

Então, (x-5)³ = x³ - 15x² + 75x - 125

D. (2-3y)³

(2-3y)³ = (2-3y)(2-3y)(2-3y)

= (2-3y)(4-12y+9y²)

= 8 - 36y + 54y² - 27y³

Portanto, (2-3y)³ = 8 - 36y + 54y² - 27y³

E. (3y-5)³

(3y-5)³ = (3y-5)(3y-5)(3y-5)

= (3y-5)(9y²-30y+25)

= 27y³ - 135y² + 225y - 125

Então, (3y-5)³ = 27y³ - 135y² + 225y - 125.