[tex]\large \text {$ a) ~6x-80^o~ e ~4~.~(x - 5^o) $}\\\\\large \text {$\Rightarrow ~ 100^o $}[/tex]
[tex]\large \text {$ b) ~4x-19^o~ e ~65^o - 3x $}\\\\\large \text {$\Rightarrow ~ 29^o$}[/tex]
[tex]\Large \text {$\hat{A} ngulos ~Congruentes $}[/tex]
Ângulos congruentes: são ângulo que possuem a mesma medida.
[tex]\large \text {$ a) ~6x-80^o~ e ~4(x - 5^o) $}[/tex]
[tex]\large \text {$ 6x-80 = 4(x - 5)$}\\\\\large \text {$6x-80 = 4x - 20$}\\\\\large \text {$6x - 4x = -20 + 80$}\\\\\large \text {$ 2x = 60 $}\\\\\\\large \text {$x = \dfrac{60}{2}$}\\\\\\\large \text {$x = 30$}[/tex]
Substituir o valor de x nos ângulos indicados.
[tex]\large \text {$ 6x-80 = 4~.~(x - 5)$}\\\\\large \text {$ 6 ~. ~30 -80 = 4~.~( 30 - 5)$}\\\\\large \text {$ 180 -80 = 4~.~( 25)$}\\\\\large \text {$ 100 = 100$}[/tex]
---
[tex]\large \text {$ b) ~4x-19^o~ e ~65^o - 3x $}[/tex]
[tex]\large \text {$ 4x-19 = 65 - 3x$}\\\\\large \text {$ 4x+ 3x = 65+ 19$}\\\\\large \text {$ 7x = 84$}\\\\\\\large \text {$ x = \dfrac{84}{7}$}\\\\\\\large \text {$ x =12$}[/tex]
[tex]\large \text {$ 4x-19 = 65 - 3x$}\\\\\large \text {$ 4 ~. 12-19 = 65 - 3 ~. ~12$}\\\\\large \text {$ 48 -19 = 65 - 362$}\\\\\large \text {$29^o = 29^o$}[/tex]
===
Para saber mais:
https://brainly.com.br/tarefa/31732470
https://brainly.com.br/tarefa/3549184
https://brainly.com.br/tarefa/175147
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[tex]\large \text {$ a) ~6x-80^o~ e ~4~.~(x - 5^o) $}\\\\\large \text {$\Rightarrow ~ 100^o $}[/tex]
[tex]\large \text {$ b) ~4x-19^o~ e ~65^o - 3x $}\\\\\large \text {$\Rightarrow ~ 29^o$}[/tex]
[tex]\Large \text {$\hat{A} ngulos ~Congruentes $}[/tex]
Ângulos congruentes: são ângulo que possuem a mesma medida.
[tex]\large \text {$ a) ~6x-80^o~ e ~4(x - 5^o) $}[/tex]
[tex]\large \text {$ 6x-80 = 4(x - 5)$}\\\\\large \text {$6x-80 = 4x - 20$}\\\\\large \text {$6x - 4x = -20 + 80$}\\\\\large \text {$ 2x = 60 $}\\\\\\\large \text {$x = \dfrac{60}{2}$}\\\\\\\large \text {$x = 30$}[/tex]
Substituir o valor de x nos ângulos indicados.
[tex]\large \text {$ 6x-80 = 4~.~(x - 5)$}\\\\\large \text {$ 6 ~. ~30 -80 = 4~.~( 30 - 5)$}\\\\\large \text {$ 180 -80 = 4~.~( 25)$}\\\\\large \text {$ 100 = 100$}[/tex]
---
[tex]\large \text {$ b) ~4x-19^o~ e ~65^o - 3x $}[/tex]
[tex]\large \text {$ 4x-19 = 65 - 3x$}\\\\\large \text {$ 4x+ 3x = 65+ 19$}\\\\\large \text {$ 7x = 84$}\\\\\\\large \text {$ x = \dfrac{84}{7}$}\\\\\\\large \text {$ x =12$}[/tex]
Substituir o valor de x nos ângulos indicados.
[tex]\large \text {$ 4x-19 = 65 - 3x$}\\\\\large \text {$ 4 ~. 12-19 = 65 - 3 ~. ~12$}\\\\\large \text {$ 48 -19 = 65 - 362$}\\\\\large \text {$29^o = 29^o$}[/tex]
===
Para saber mais:
https://brainly.com.br/tarefa/31732470
https://brainly.com.br/tarefa/3549184
https://brainly.com.br/tarefa/175147