Encontre o ponto P(x,y), que é comum as retas ( utilizando para resolução o sistema linear)
(r): x-3y -5 =0
(s): x +y -2=0
(r): x-3y -5 =0
(s): x +y -2=0
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Resposta:
(r): x-3y -5 =0 (i)
(s): x +y -2=0 (ii)
(i)-(ii)
x-x-3y-y -5-(-2) =0
-4y-3=0 ==y=-3/4
usando (i) ==> x-3*(-3/4)-5=0 ==>x+9/4-5=0
==>4x+9-20=0 ==>x=11/4
P(x,y)=(11/4 , -3/4)