consommation à moulin=6xd/100
consommation a vichy=(50-d)x9/100
comme meme consommation : 6xd=(50-d)x9
6d+9d=450
15d=450
d=450/15=30km
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consommation à moulin=6xd/100
consommation a vichy=(50-d)x9/100
comme meme consommation : 6xd=(50-d)x9
6d+9d=450
15d=450
d=450/15=30km