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Cino
@Cino
June 2021
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La factorisation, vous y arrivez ? Moi d'habitude, oui, mais dès qu'il y a des carrés et tout les trucs ... Ca m'embrouille ! J'ai développé mais pas factorisé ..
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winner123
Verified answer
Bonsoir
A = x² - 10 x +25 - ( 2 x² - 10 x - 7 x + 35)
A = x² - 10 x + 25 - 2 x² + 10 x + 7 - 35
A = - x² - 3
A = ( x -5) ( x - 5 - 2 x + 7)
A = ( x - 5) ( - x + 2)
B = 6 x² - 3 x + 10 x - 5 + 9 x² - 25
B = 15 x² + 7 x - 30
B : 9 x² - 25 = ( 3 x -5) ( 3 x +5)
donc
B = (3 x +5) ( 2 x - 1 + 3 x - 5)
b = ( 3 x +5 ) ( 5 x - 6)
1 votes
Thanks 1
Cino
Merci beaucoup, ça m'sauve ! :D
em237972
1)
Développement
.
A = (x² - 10x + 25) - (2x² - 10x - 7x + 35)
A = x² - 10x + 25 - 2x² + 10x + 7x - 35
A = -x² + 32x - 35.
B = 6x² - 3x + 10x - 5 + 9x² - 25
B = 15x² + 7x - 30.
2)
Factorisation
.
A = (x - 5 - 2x + 7)(x - 5)
A = (-x + 2)(x - 5).
B = (3x + 5)(2x - 1 + 3x - 5)
B = (3x + 5)(5x - 6).
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Verified answer
BonsoirA = x² - 10 x +25 - ( 2 x² - 10 x - 7 x + 35)
A = x² - 10 x + 25 - 2 x² + 10 x + 7 - 35
A = - x² - 3
A = ( x -5) ( x - 5 - 2 x + 7)
A = ( x - 5) ( - x + 2)
B = 6 x² - 3 x + 10 x - 5 + 9 x² - 25
B = 15 x² + 7 x - 30
B : 9 x² - 25 = ( 3 x -5) ( 3 x +5)
donc
B = (3 x +5) ( 2 x - 1 + 3 x - 5)
b = ( 3 x +5 ) ( 5 x - 6)
A = (x² - 10x + 25) - (2x² - 10x - 7x + 35)
A = x² - 10x + 25 - 2x² + 10x + 7x - 35
A = -x² + 32x - 35.
B = 6x² - 3x + 10x - 5 + 9x² - 25
B = 15x² + 7x - 30.
2) Factorisation .
A = (x - 5 - 2x + 7)(x - 5)
A = (-x + 2)(x - 5).
B = (3x + 5)(2x - 1 + 3x - 5)
B = (3x + 5)(5x - 6).