OR=OS=8cm => RQ=16cm
∠QSR=90°
RS=7cm
SQ=√(RS²-RS²)=√207
ΔQTO≈ΔQSR => OT=1/2*RS=1/2*7=3.5cm
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OR=OS=8cm => RQ=16cm
∠QSR=90°
RS=7cm
SQ=√(RS²-RS²)=√207
ΔQTO≈ΔQSR => OT=1/2*RS=1/2*7=3.5cm