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amandacoimbra1
@amandacoimbra1
October 2020
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ME AJUDEM!
Determine a medida X indicada no triângulo acutângulo abaixo:
o angulo A mede 60°
a reta AB 8 cm
o angulo C mede 45°
a reta BC mede X
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Kazuyoshi
Basta utilizar a lei dos Senos:
x/√3/2 = 8/√2/2
x = (8√3/2)/√2/2
x = 8√3/2 * 2/√2
x = 16√3/2√2
x = 16√3/2√2 * 2√2/2√2
x = 32√5/4*2
x = 32√5/8
x = 4√5
36 votes
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x/√3/2 = 8/√2/2
x = (8√3/2)/√2/2
x = 8√3/2 * 2/√2
x = 16√3/2√2
x = 16√3/2√2 * 2√2/2√2
x = 32√5/4*2
x = 32√5/8
x = 4√5