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Ikraaaaam
@Ikraaaaam
April 2019
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Merci pour votre aide !
On considère A=(3x-5)²-49
1. Développer puis réduire A.
2. Calculer A pour x=V3 (donner une valeur exacte et une valeur approchée à 0.1 près)
**V = racine carrée
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winner123
Verified answer
Bonsoir
A = ( 3 x - 5)² - 49
A ) 9 x² - 30 x + 25 - 49
a = 9 x² - 30 x - 24
pour x = √3
A = 9 (√3)² - 30√3 - 24
A = 27 - 30 √3 - 24
A = 3 - 30√3
0 votes
Thanks 1
loulakar
Verified answer
1) développer et réduire :
A=9x^2-30x+25-49
A=9x^2-30x-24
2) calcul de A pour x=V3
A=9*(V3)^2-30V3-24
A=9*3-30V3-24
A=27-24-30V3
A=3-30V3
A=3(1-10V3)
A=3(1-10*1,732)
A=3(1-17,32)
A=3*(-16,32)
A=(-48,96)
0 votes
Thanks 1
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Lista de comentários
Verified answer
BonsoirA = ( 3 x - 5)² - 49
A ) 9 x² - 30 x + 25 - 49
a = 9 x² - 30 x - 24
pour x = √3
A = 9 (√3)² - 30√3 - 24
A = 27 - 30 √3 - 24
A = 3 - 30√3
Verified answer
1) développer et réduire :A=9x^2-30x+25-49
A=9x^2-30x-24
2) calcul de A pour x=V3
A=9*(V3)^2-30V3-24
A=9*3-30V3-24
A=27-24-30V3
A=3-30V3
A=3(1-10V3)
A=3(1-10*1,732)
A=3(1-17,32)
A=3*(-16,32)
A=(-48,96)